## Sample 1 - Power Flow Configuration |

When there is more than one bleeder, the user has the option to specify if the total bleeder power is:

1. Divided equally among all bleeders2. Divided proportionally to each bleederâ€™s continuous power ratingExample

If the total required braking power, P_{Total}= 1000W and there are n = 2 bleeders

Then the continuous power through each bleeder is:

P_{1}= P_{2}= P_{Total}/ n = 1000 / 2 = 500W

3. Divided proportionally to resistor current. Ie. All choppers are synchronized such that they engage and disengage simultaneously.

ExampleIf the total required braking power, P_{Total}= 1000W, P_{1Rating}= 250W and P_{2Rating}= 1000W

Then the continuous power through each bleeder is:

P_{1}= P_{Total}x P_{1Rating}/ (P_{1Rating}+ P_{2Rating}) = 1000 x 250 / (250 + 1000) = 200W

P_{2}= P_{Total}x P_{2Rating}/ (P_{1Rating}+ P_{2Rating}) = 1000 x 1000 / (250 + 1000) = 800W

ExampleIf the total required braking power, P_{Total}= 1000W, R_{1}= 50 Ohms and R_{2}= 10 Ohms

Then the continuous power through each bleeder is:

P_{1}= P_{Total}x 1/R_{1}/ (1/R_{1}+ 1/R_{2}) = 1000 x 1/50 / (1/50 + 1/10) = 167W

P_{2}= P_{Total}x 1/R_{2}/ (1/R_{1}+ 1/R_{2}) = 1000 x 1/10 / (1/50 + 1/10) = 833W